![image](https://www.notion.so/image/https%3A%2F%2Fs3-us-west-2.amazonaws.com%2Fsecure.notion-static.com%2F0eae9b44-bcbb-4d43-9b7a-157724d02071%2FForce.png?id=d746c799-0d28-4bce-88f0-3911a16fbfe3&table=block)
The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder.
Force (F) = Hydraulic Working Pressure (P) x Cylinder Effective Area (A)
Example 1:
An RC106 cylinder with 2.24 in2 effective area is operating at 8,000 psi. What force is being generated? Force = 8,000 psi x 2.24 in2 = 17,920 lbs
Example 2:
An RC106 cylinder has to lift 14,000 lbs of force. What pressure is required? Pressure = 14,000 lbs ÷ 2.24 in2 = 6,250 psi
Example 3:
An RC256 cylinder with 5.15 in2 effective area is required to produce a force of 41,000 lbs. What pressure is required? Pressure = 41,000 lbs ÷ 5.15 in2 = 7,961 psi
Example 4:
Four RC308 cylinders each with 6.49 in2 effective area are required to produce a force of 180,000 lbs. What pressure is required? Pressure = 180,000 lbs ÷ (4 x 6.49 in2) = 6,933 psi (Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used).