The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder.

**Force (F) = Hydraulic Working Pressure (P) x Cylinder Effective Area (A)**

**Example 1:**

An * RC106* cylinder with 2.24 in² effective area is operating at 8,000 psi.
What force is being generated?

**Force**= 8,000 psi x 2.24 in² = 17,920 lbs

**Example 2:**

An * RC106* cylinder has to lift 14,000 lbs of force.
What pressure is required?

**Pressure**= 14,000 lbs ÷ 2.24 in² = 6,250 psi

**Example 3:**

An * RC256* cylinder with 5.15 in² effective area is required to produce a force of 41,000 lbs.
What pressure is required?

**Pressure**= 41,000 lbs ÷ 5.15 in² = 7,961 psi

**Example 4:**

Four * RC308* cylinders each with 6.49 in² effective area are required to produce a force of 180,000 lbs.
What pressure is required?

**Pressure**= 180,000 lbs ÷ (4 x 6.49 in²) = 6,933 psi (Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used).